5t^2-2t+10=0

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Solution for 5t^2-2t+10=0 equation:


Simplifying
5t2 + -2t + 10 = 0

Reorder the terms:
10 + -2t + 5t2 = 0

Solving
10 + -2t + 5t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
2 + -0.4t + t2 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -0.4t + -2 + t2 = 0 + -2

Reorder the terms:
2 + -2 + -0.4t + t2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -0.4t + t2 = 0 + -2
-0.4t + t2 = 0 + -2

Combine like terms: 0 + -2 = -2
-0.4t + t2 = -2

The t term is -0.4t.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4t + 0.04 + t2 = -2 + 0.04

Reorder the terms:
0.04 + -0.4t + t2 = -2 + 0.04

Combine like terms: -2 + 0.04 = -1.96
0.04 + -0.4t + t2 = -1.96

Factor a perfect square on the left side:
(t + -0.2)(t + -0.2) = -1.96

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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